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8x^2+9=809
We move all terms to the left:
8x^2+9-(809)=0
We add all the numbers together, and all the variables
8x^2-800=0
a = 8; b = 0; c = -800;
Δ = b2-4ac
Δ = 02-4·8·(-800)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*8}=\frac{-160}{16} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*8}=\frac{160}{16} =10 $
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